We have collected the most relevant information on Catch Unsupportedaudiofileexception. Open the URLs, which are collected below, and you will find all the info you are interested in.
java - UnsupportedAudioFileException with a .wav file ...
https://stackoverflow.com/questions/63061511/unsupportedaudiofileexception-with-a-wav-file
It's structured like this: -src -app -audio EnviromentAudio.java // Class that need to load soundtrack.wav -res -audio Soundtrack.wav // Audio to be loaded. And I know that a getResource.. should start always with a /, but if I add that slash, then every attempt to get a resource results in a NPE. Probably that's caused by the folders ...
javax.sound.sampled.UnsupportedAudioFileException java ...
https://www.tabnine.com/code/java/classes/javax.sound.sampled.UnsupportedAudioFileException
error ( "URL is in an unsupported audio file format: " + e. getMessage ()); origin: marytts / marytts. throw new UnsupportedAudioFileException ( "Conversion from audio format " + ais.getFormat () + " to requested audio format " + targetFormat + " not supported.\n" + iae.getMessage ()); origin: marytts / marytts.
javax.sound.sampled.Clip java code examples | Tabnine
https://www.tabnine.com/code/java/classes/javax.sound.sampled.Clip
this. pack (); this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); this. setVisible (true); try { AudioInputStream audioInputStream = AudioSystem. getAudioInputStream (url); clip = AudioSystem. getClip (); clip. open (audioInputStream); } catch (UnsupportedAudioFileException e) { e.printStackTrace(); if (clip. isRunning ()) clip. stop (); // Stop the player if it is still running …
Playing a wav file in a java application [SOLVED ... - DaniWeb
https://www.daniweb.com/programming/software-development/threads/346655/playing-a-wav-file-in-a-java-application
private void playSound(String file) { try { Clip sound = AudioSystem.getClip(); sound.open(AudioSystem.getAudioInputStream( getClass().getResource(file))); sound.start(); } catch (UnsupportedAudioFileException e1) { } catch (IOException e2) { } catch (LineUnavailableException e3) { } } So that you can do: Jump to Post
javax.sound.sampled.Clip.loop java code examples | Tabnine
https://www.tabnine.com/code/java/methods/javax.sound.sampled.Clip/loop
Best Java code snippets using javax.sound.sampled. Clip.loop (Showing top 20 results out of 315) Common ways to obtain Clip. private void myMethod () {. C l i p c =. AudioSystem.getClip () Line.Info info; (Clip) AudioSystem.getLine (info) Smart code suggestions by Tabnine. }
Play Sound in Java - Delft Stack
https://www.delftstack.com/howto/java/play-sound-in-java/
Below are the steps involved: The first step is to create an object of the audio input stream. This step converts the audio file into an input stream that the app can use. The third step is now to load the clip object with audio data from the audio input stream that was created in step 1. You can then start the clip.
Now you know Catch Unsupportedaudiofileexception
Now that you know Catch Unsupportedaudiofileexception, we suggest that you familiarize yourself with information on similar questions.
