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Solved A student uses an audio oscillator of adjustable ...
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A student uses an audio oscillator of adjustable frequency to measure the depth of a water well. The student reports hearing two sucessive resonances at 54.30 Hz and 61.75 Hz. Assume speed of sound in air is 343 m/s.
Student Audio Oscillator Adjustable Frequency Measure Depth
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A student uses an audio oscillator of adjustable frequency to measure the depth of a water well. The student reports hearing two successive resonances at 54.30 Hz and 61.75 Hz. Assume speed of sound in air is 343 m/s. a). how deep is the well? b). how many antinodes are in the standing wave at 54.30 Hz? Edit Added Fri, 18 Dec '15 UladKasach 2509
Solved A student uses an audio oscillator of adjustable ...
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A student uses an audio oscillator of adjustable frequency to measure the depth of a water well. The student reports hearing two successive resonances at 53.95 Hz and 59.00 Hz. (Assume that the speed of sound in air is 343 m/s.) (a) How deep is the well? (b) How many antinodes are in the standing wave at 53.95 Hz? Expert Answer 80% (5 ratings)
Answered: A student uses an audio oscillator of… | bartleby
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First week only $4.99! arrow_forward. We've got the study and writing resources you need for your assignments. Start exploring! Science Physics Q&A Library A student uses an audio oscillator of adjustable frequency to measure the depth of a water well. He reports hearing two successive resonances at 52.0 Hz and 60.0 Hz.
A student uses an audio oscillator of adjustable …
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Find step-by-step Physics solutions and your answer to the following textbook question: A student uses an audio oscillator of adjustable frequency to measure the depth of a water well. The student reports hearing two successive resonances at 51.87 Hz and 59.85 Hz. (a) How deep is the well? (b) How many antinodes are in the standing wave at 51.87 Hz?.
Using Waves to Find Depth of Well - Physics Forums
https://www.physicsforums.com/threads/using-waves-to-find-depth-of-well.818769/
A student uses an audio oscillator of adjustable frequency to measure the depth of a dried up well. Two successive resonances are heard at 17.0Hz and 23.8Hz. The speed of sound in air is 343 m/s. How deep is the well? Homework Equations f=nv/4L The Attempt at a Solution [/B] I solved the problem and the answer was 25.22m.
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