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Digital audio concepts - Web media technologies | MDN
https://developer.mozilla.org/en-US/docs/Web/Media/Formats/Audio_concepts#:~:text=The%20size%20of%20an%20audio%20frame%20is%20calculated,%284%20bytes%20per%20sample%20multiplied%20by%206%20channels%29.
pcm - WAV - Bytes per video frame - Sound Design Stack ...
https://sound.stackexchange.com/questions/46208/wav-bytes-per-video-frame
I want to find out the amount of bytes that is contained within a "frame" of audio, correlating it to a frame of video data. My script delivers me a chunk size of 4096 bytes. Trying to calculate this ahead of time has been problematic for me since I thought the formula was: 48.000 / 20 * samplesize
Digital audio concepts - Web media technologies | MDN
https://developer.mozilla.org/en-US/docs/Web/Media/Formats/Audio_concepts
Each audio frame is a data record that contains the samples for all of the channels available in an audio signal. The size of an audio frame is calculated by multiplying the sample size in bytes by the number of channels, so a single frame of stereo 16-bit audio is 4 bytes long and a single frame of 5.1 floating-point audio is 24 (4 bytes per sample multiplied by 6 channels).
MP3 Bytes per frame?
https://hydrogenaud.io/index.php?topic=32036.0
For MPEG-1.0 Layer-III and Layer-II the samples per frame is 1152 bytes. For MPEG-1.0 Layer-I it's 384 bytes. For MPEG-2.0 and MPEG-2.5, Layer-I is 384 bytes, Layer-II is 1152 bytes, and Layer-III is 576 bytes. PaddingSize is determined by the layer number. Layer-I is 4 bytes and Layer-II and Layer-III are 1 byte.
python - What does a audio frame contain? - Stack Overflow
https://stackoverflow.com/questions/3957025/what-does-a-audio-frame-contain
A frame appears to be somewhat like stride in graphics formats. For interleaved stereo @ 16 bits/sample, the frame size is 2*sizeof(short) =4 bytes. For non-interleaved stereo @ 16 bits/sample, the samples of the left channel are …
FramesPeriods - AlsaProject
https://www.alsa-project.org/main/index.php/FramesPeriods
1 analog sample is represented with 16 bits = 2 bytes; 1 frame represents 1 analog sample from all channels; here we have 2 channels, and so: 1 frame = (num_channels) * (1 sample in bytes) = (2 channels) * (2 bytes (16 bits) per sample) = 4 bytes (32 bits)
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